RaisaSaif04 RaisaSaif04

01-04-2017
Physics

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A spring of 1 kg is attached to a spring which produces an extension of 0.1 cm its spring constant

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jtagardiner jtagardiner

01-04-2017

F=m·a
F=(1kg)(9.81m/s²)
F=9.81N

0.1cm=0.001m

k=Fs/x
k=9.81N/0.001m
The final answer is k=9810N/m

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